Math

We have two integers, $x$ and $y$.

$x*y = -12$

$x + y = -3$

$y = -3-x$

$x*(-3-x) = -12$

$-x^2 - 3x + 12 = 0$

Now, we can use the quadratic formula to find the two factors: $\frac{-b ± \sqrt{b^2 - 4ac}}{2a}$.

$\frac{3 ± \sqrt{57}}{-2}$, so the two roots are $\frac{3 - \sqrt{57}}{-2}$ and $\frac{3 + \sqrt{57}}{-2}$. These two numbers are the only numbers that have a product of $-12$ and a sum of $-3$, BUT, they are NOT integers.

- Daisy

Hi DS it is really good to see you again :)