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Don't know how to do these questions......

1) A mother says to her daughter, "When I was your age, you were only 7. But when you become my age, I will be 88 years old. What is the present age of the mother and that of the daughter?

 

2) In a meeting, everyone shakes hands with another person. If the total number of shaking hands is 2016 times, how many people was in the meeting?

 Nov 29, 2016

Best Answer 

 #4
avatar+37165 
+10

Thanx!  heureka....

 Nov 30, 2016
 #1
avatar+37165 
+5

#1

Mom age = x

Daughter age = y

 

age difference  = x-y

Now, the Daughter's age MINUS the age difference equals  7

y-(x-y) = 7  or  2y-x=7     (Equation 1)

AND the Mother's age PLUS the age difference is 88

x+(x-y) = 88  or 2x-y =88  ((Equation 2)

 

From equation 1 :    x = 2y-7    Sustitute into equation 2

                              2(2y-7) - y =88    solve for y =34       = daughter's age     

 

 

Equation 1 again  2y-x=7    2(34) - x = 7     x = 61= mom's age

 Nov 29, 2016
 #2
avatar+37165 
+5

 

#2  Not sure.....     do you mean that everyone there shakes hands with eveyone else there?

 Nov 29, 2016
edited by ElectricPavlov  Nov 29, 2016
 #3
avatar+26396 
+10

2) In a meeting, everyone shakes hands with another person.

If the total number of shaking hands is 2016 times,

how many people was in the meeting?

 

Let n = people in the meeting

n(n1)2=2016 handshakes n(n1)=4032n2n=4032n2n4032=0n=1+14(4032)2n=1+161292n=1+1272n=1282n=64

 

 

laugh

 Nov 30, 2016
 #4
avatar+37165 
+10
Best Answer

Thanx!  heureka....

ElectricPavlov  Nov 30, 2016
 #5
avatar+9675 
0

Thanks everyone :)

 Dec 1, 2016

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