Need some help with differential equations.

Question

0

1514

1

+9675

Solve:

$y'' - \omega^2y = 0, y(0)=1,y'(0)=1\\\text{Assuming }\omega \neq 0$

MaxWong Jul 25, 2017

Alan · Answer 1 · 2017-07-25T06:19:29

Like so:

$y=Ae^{\omega x}+Be^{-\omega x}\\ y'=\omega Ae^{\omega x}-\omega Be^{-\omega x}\\ y''= \omega^2y$

Now use your initial conditions to find A and B.