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Can't figure out all of the non-permissible values of (cot(x))/(2sin^2(x)-1).

So far I've got 0, 1 and pi +npi (n being any integer) but I'm not even sure if those are right. Any help would be much appreciated. 

 Jan 16, 2018
 #1
avatar+118713 
+2

Can't figure out all of the non-permissible values of (cot(x))/(2sin^2(x)-1).

So far I've got 0, 1 and pi +npi (n being any integer) but I'm not even sure if those are right. Any help would be much appreciated. 
Cotx=cos(x)sin(x)So it is not defined when sin(x)=0 which is when x is any integer multiple of π So the non permissable values of x will include x=nπWhere n is any integer

 

ALSO

The deominator cannot equal 0 so 

 

2sin2x10sin2x12sinx±12xπ4+nπ2xπ4(1+2n)nZ

 

so the non-permsissable values are 

 

x=nπandx=π4(2n+1)nZ

 

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I have written this in LaTex which I think other people will be able to properly but it will not display properly for me.

Once I hit the preview button it will only show the raw code. When I hit post it will still only show the raw code.  crying

Yes as I expected.  sad sad

 Jan 16, 2018
 #2
avatar+119 
+2

Thanks!!! It finally makes sense to me.

Aleguan  Jan 16, 2018

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