A Ferris wheel completes 7 revolutions in 14 minutes. The radius of the Ferris Wheel is 30 feet.
What is the linear velocity of the Ferris Wheel in inches per second?
Enter your answer rounded to the nearest tenth.
7 revolutions in 14 minutes means an average of 1 revolution per 2 minute.
That means the angular velocity of the Ferris wheel is \(\omega = \dfrac{2\pi}{120}\text{ rad s}^{-1} =\dfrac\pi{60} \text{ rad s}^{-1}\).
Using the formula \(v = r \omega\), we have the linear velocity = \(v = (30)\left(\dfrac\pi{60}\right) = \dfrac\pi2 \text{ ft s}^{-1}\).
Edit: That's 1.6 ft/s if you round it off to the nearest tenth.