If the chance of an overnight freeze in Rexburg on any given night is 0.55, what is the probability that it will freeze one or more of the next 14 nights in Rexburg?
+130466 "One or more nights' is the same thing as saying "at least" one night.
And the probability of freezing at least one night is the same probability as 1 minus the probability that it doesn't freeze ANY of those nights. And the probability that it doesn't freeze on any particular night is 45% or just .45
So we have .....
1 - (.45)14 = 0.9999860371139801 .......(In effect, it's almost guaranteed to freeze on at least one night!!)
+130466 "One or more nights' is the same thing as saying "at least" one night.
And the probability of freezing at least one night is the same probability as 1 minus the probability that it doesn't freeze ANY of those nights. And the probability that it doesn't freeze on any particular night is 45% or just .45
So we have .....
1 - (.45)14 = 0.9999860371139801 .......(In effect, it's almost guaranteed to freeze on at least one night!!)
