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In mathematics, we have positive number,

take the negative of it and we get a negative number. 

take the square root of the negative number we get a imaginary number.

add the imaginary number to a real number we get a complex number.

and can we derive anything out of complex number or we just stop there? I feel like the vast ocean of Mathematics is hiding something from me.

 

~The smartest cookie in the world

 Jan 7, 2017

Best Answer 

 #4
avatar+33654 
+10

Perhaps you would be interested in quaternions Max (see https://en.wikipedia.org/wiki/Quaternion for example).  These extend the concept of complex numbers.

 Jan 8, 2017
 #1
avatar+9675 
0

Can someone answer this please...... My curiousity is telling me to take this knowledge ASAP......

 Jan 7, 2017
 #2
avatar+118703 
+5

Hi Max,

How about:

ii=realnumber

 

proof:

ii=elnii=eilniFor complex logsln(z)=ln|z|+iarg(z)soln(i)=ln|i|+iarg(i)=ln(1)+iπ2=iπ2 soii=elnii=eilni=eiiπ2=e1π2=eπ2

 

So maybe we start going in circles    frown

 Jan 8, 2017
 #6
avatar+9675 
+5

Maybe.

 

Let's think about (ii)i which is eiπ/2=e1/2ln(1)=(eln(1))1/2=1=i

 

Then think about ((ii)i)i which is

ii=eiπ/2

 

We just go in imaginary -> real -> imaginary -> real -> ......... circles.

 

We can conclude that:

 

((ii).......)i with odd number of i=i((ii).......)i with even number of i=eπ/2

MaxWong  Jan 8, 2017
 #3
avatar+118703 
+5

I had a thought,

Any number divided by itself =1,  even complex numbers.

 

and

If you multiply a complex number by its conjugate you get a real number too :)

 Jan 8, 2017
 #4
avatar+33654 
+10
Best Answer

Perhaps you would be interested in quaternions Max (see https://en.wikipedia.org/wiki/Quaternion for example).  These extend the concept of complex numbers.

Alan Jan 8, 2017
 #5
avatar+9675 
0

Thank you!! That is really awesome!! 

MaxWong  Jan 8, 2017

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