So we have:
start=a1=4increase=d=3term number=n=50term 50=an=a50?an=a1+(n−1)∗da50=4+(50−1)∗3a50=4+49∗3a50=151
Latex code:
} = a_1=4\\
\mbox{increase}=d=3\\
\mbox{term number}=n=50\\
\mbox{term 50}=a_n=a_{50}?\\
\boxed{a_n=a_1+(n-1)*d}\\
a_{50}=4+(50-1)*3\\
a_{50}=4+49*3\\
\boxed{a_{50}=151}
Term 50 is 151
So we have:
start=a1=4increase=d=3term number=n=50term 50=an=a50?an=a1+(n−1)∗da50=4+(50−1)∗3a50=4+49∗3a50=151
Latex code:
} = a_1=4\\
\mbox{increase}=d=3\\
\mbox{term number}=n=50\\
\mbox{term 50}=a_n=a_{50}?\\
\boxed{a_n=a_1+(n-1)*d}\\
a_{50}=4+(50-1)*3\\
a_{50}=4+49*3\\
\boxed{a_{50}=151}
Term 50 is 151