Tank A measuring 40 cm by 20 cm by 80 cm,is filled with water to the brim.Tank B is an empty rectangular container with a base area of 60 cm by 40 cm.What is the volume of water that must be poured into Tank B from Tank A such that they have the same height in the end?
Tank A measuring 40 cm by 20 cm by 80 cm,is filled with water to the brim.Tank B is an empty rectangular container with a base area of 60 cm by 40 cm.What is the volume of water that must be poured into Tank B from Tank A such that they have the same height in the end?
20cm∗40cm∗(80cm−h)=40cm∗60cm∗h20cm∗(80cm−h)=60cm∗h|:20cm80cm−h=3h4h=80cmh=20cm
What is the volume of water that must be poured into Tank B from Tank A such that they have the same height in the end?
V=40cm∗60cm∗h=40∗60∗20cm3=48000cm3
So, assuming that 80 cm is the height of the first tank, the volume of water in the first tank =
40*20*80 = 64000cm^3
Note that the volume of water remains constant and is divided between the two tanks thusly:
40*20*h + 60*40*h = 64000
800h + 2400h = 64000
3200h = 64000
h = 20
So, both tanks would be filled to a height of 20cm
And the volume of water that would be poured from Tank A = 40*20*(80-20) =
48000cm^3
Tank A measuring 40 cm by 20 cm by 80 cm,is filled with water to the brim.Tank B is an empty rectangular container with a base area of 60 cm by 40 cm.What is the volume of water that must be poured into Tank B from Tank A such that they have the same height in the end?
20cm∗40cm∗(80cm−h)=40cm∗60cm∗h20cm∗(80cm−h)=60cm∗h|:20cm80cm−h=3h4h=80cmh=20cm
What is the volume of water that must be poured into Tank B from Tank A such that they have the same height in the end?
V=40cm∗60cm∗h=40∗60∗20cm3=48000cm3