the sum of three consecutive odd integers is equal to 18 less that 5 times the middle integer. Find the three integers.
Let the smallest integer be n. Then we have n + (n+2) + (n+4) = 5*(n+2)-18 or
3n + 6 = 5n -8
14 = 2n
n = 7
n+2 = 9
n+4 =11
