there are three consecutive integers. half of the sum of the second and third is 35. what are the integers

1. Number: i

2. Number: i+1

3. Number: i+2

$$\\{(2.\;Number + 3.\;Number) \over 2 }= 35\\\\ {((i+1)+ (i+2)) \over 2 }= 35 \\\\ {(2i+1+2)\over 2 }= 35 \\\\ {(2i+1) \over 2 }+1 = 35 \\\\ {(2i+1) \over 2 } =34 \quad | \quad \mbox{2i+1 is an odd number}$$

an odd number cannot be divided by 2

Here is no solution!

Unless consecutive can be interpreted differently form how I would interprete it this is impossible.

Consider just the 2nd and the 3rd integer.

One is even and one is odd.  When you add them you get an odd number.  

When you divide this by 2  you get something and a half.  It cannot be a whole number.

Right on, Melody....it you try it, the first "integer" will be 33.5........this problem is missing something......