Trig Ratios

Let a triangle with any two sides with length a and b exists.

Let the angle between a and b be $\theta$

The height 'h' = $a\sin \theta$OR $b\sin \theta$

The base = b if "height = a sin theta" is true OR = a if "height = b sin theta" is true.

Therefore Area of Any Triangle = $\dfrac{ab\sin \theta}{2}$