What are the zeros of the polynomial function?
f(x)=x3+x2−9x−9f(x)=x2(x+1)−9(x+1)f(x)=(x2−9)(x+1)f(x)=(x+3)(x+1)(x−3)∴-3, -1 and 3 are zeros of the polynomial.
(x^3 + x^2 - 9x - 9) : (x + 1) = x^2 - 9 x^3 + x^2 ——————— - 9x - 9 - 9x - 9 ———— 0
x^2 - 9 = (x + 3) (x - 3)
x = -1
x = -3
x = 3