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what is the answer to : the absolute value of l2x +6I-4=-20

 Apr 25, 2016
 #1
avatar+128731 
0

l 2x + 6 l   - 4  = -20   add 4 to both sides

 

l 2x + 6 l   = -16

 

Note that this has no solution because absolute value is always positive (or 0).......thus, the left side [ a positive, or zero] cannot equal the right side [ a negative]

 

 

cool cool cool

 Apr 25, 2016
 #2
avatar+9664 
+4

l 2x + 6 l - 4 = -20

l 2x + 6 l + 16 = 0

2x + 22 = 0

x + 11 = 0

x = -11

Am i wrong?

 Apr 26, 2016
 #3
avatar+128731 
0

Sorry, Max.....I believe you made an error....look at your second step....you have.....

 

l 2x + 6  l  + 16 = 0       (1)

 

If we claim that the answer is -11, then we have

 

l 2(-11) + 6 l + 16 = 0

 

l -22 + 6 l  + 16  = 0

 

l -16 l + 16   = 0

 

16 + 16   = 0

 

32  = 0     .......which is clearly false

 

We have no solution because the left side of (1)   will always be >  0

 

 

cool cool cool

 Apr 26, 2016

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