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writing sinh inverse (-(48/55)) in logarithim form

 Jul 7, 2014

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 #2
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writing sinh inverse (-(48/55)) in logarithim form

sinh1(x)=ln(x+x2+1)sinh1(4855)=ln(4855+(4855)2+1)=ln(0.45454545455)=0.78845736036

 Jul 7, 2014
 #1
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inverseSinh

Alan Jul 7, 2014
 #2
avatar+26396 
+6
Best Answer

writing sinh inverse (-(48/55)) in logarithim form

sinh1(x)=ln(x+x2+1)sinh1(4855)=ln(4855+(4855)2+1)=ln(0.45454545455)=0.78845736036

heureka Jul 7, 2014

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