Loading [MathJax]/jax/output/SVG/config.js
 
+0  
 
+5
712
6
avatar

x^2+1.09*10^{-12}-0.00000128*x=0

 Mar 8, 2016
 #1
avatar+46 
0

We just started learning exponents and that looks really complicated sorry.

 Mar 8, 2016
 #2
avatar
0

Umm.........

I dunno

 Mar 8, 2016
 #3
avatar
0

x^2+1.09*10^{-12}-0.00000128*x=0

 

{x=-(((sqrt(559256901775944674499989479)*i-18348623853211)/28669724770642187500)), x=((sqrt(559256901775944674499989479)*i+18348623853211)/28669724770642187500)}

 

That's what the calculator said.

 Mar 8, 2016
 #4
avatar
0

Solve for x:
x^2-1.28×10^-6 x+0.355535 = 0

x^2-1.28×10^-6 x+0.355535 = x^2-1.28×10^-6 x+0.355535:
x^2-1.28×10^-6 x+0.355535 = 0

Subtract 0.355535 from both sides:
x^2-1.28×10^-6 x = -0.355535

Add 4.096×10^-13 to both sides:
x^2-1.28×10^-6 x+4.096×10^-13 = -0.355535

Write the left hand side as a square:
(x-6.4×10^-7)^2 = -0.355535

Take the square root of both sides:
x-6.4×10^-7 = 0.+0.596267 i or x-6.4×10^-7 = 0.-0.596267 i

Add 6.4×10^-7 to both sides:
x = 6.4×10^-7+0.596267 i or x-6.4×10^-7 = 0.-0.596267 i

Add 6.4×10^-7 to both sides:
Answer: |  x = 6.4×10^-7+0.596267 i    or    x = 6.4×10^-7-0.596267 i

 Mar 8, 2016
 #5
avatar+5265 
0

x^2+1.09*10^{-12}-0.00000128*x=0

 

 {x=-(((sqrt(559256901775944674499989479)*i-18348623853211)/28669724770642187500)),

x=((sqrt(559256901775944674499989479)*i+18348623853211)/28669724770642187500)}

 Mar 8, 2016
 #6
avatar+5265 
0

Calculator.

rarinstraw1195  Mar 8, 2016

2 Online Users

avatar
avatar