You are traveling on the Viper at 18.4 m/s on a hill 35.1 m high. The Viper drops you suddenly to a second hill that is 22.5 m high. How fas

Assuming the sum of kinetic and potential energy is conserved, that is (1/2)mv₁² + mgh₁ = (1/2)mv₂² + mgh₂ then (1/2)v₂² = (1/2)v₁² +g*(h₁-h₂)  or v₂ = sqrt(v₁²+2*g*(h₁-h₂))

$${\sqrt{{{\mathtt{18.4}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{9.81}}{\mathtt{\,\times\,}}\left({\mathtt{35.1}}{\mathtt{\,-\,}}{\mathtt{22.5}}\right)}} = {\mathtt{24.202\: \!727\: \!119\: \!066\: \!561\: \!9}}$$

or approximately 24.2 m/s