Alan

As follows:

The fourth root of 98 is between 3 and 4, so the only possible integer values would be 1, 2 or 3 for the fourth root.

So n must be one of  \(\frac{98}{1^4}\)  or \( \frac{98}{2^4}\) or \(\frac{98}{3^4}\)

I'll leave you to determine which of them is an integer.

This should help:

I hope the following is explanation enough:

Like so:

I'll leave you to finish.

You could also look at it like this:

L1 + L2 = 200

L1 = 4*L2

Therefore:

4*L2 + L2 = 200

etc. 

I assume you can find L2 and then L1 from the above.

Here's another way:

(Incidentally, you should check your result for b^2 - 4ac BuilderBoi).

Like so:

Can you take it from here?

As follows:

Can you take it from here?