See below:
This should allow you to answer both your questions.
Set y = 0 and solve the resulting equation for t. There will be two values; choose the only sensible one.
Thanks. You're almost right! I added the square root of 75 instead of subtracting it. I've now edited and corrected.
Like so:
\(\sqrt{12}-\sqrt{75}+\sqrt{147}=\sqrt{3*4}-\sqrt{3*25}+\sqrt{3*49}=(2-5+7)*\sqrt{3}=4\sqrt{3}\)
Like this for Q1:
Now let's see you attempt something!
See https://web2.0calc.com/questions/the-fundamental-of-calc-pt1#r1, for the approach.
Split the integral into two integrals (note the upper limit on the first integral and the lower limit on the second integral):
\(\int_{-1}^{2}f(x)dx=\int_{-1}^{1}(3-x^3)dx+\int_{1}^{2}x^2dx \)
I assume you can do these individual integrals.
Yes.
Correct!
This should help:
I should have said the turning point values of t, not x!
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