This should help:
As follows:
Copy and paste it into the calculator on the Home page here and press enter.
A general term in the expansion is (9n)(2z)nz−(9−n2)(−1)9−n
The constant term means the z terms don't appear, which means we must have n−9−n2=0 or n = 3
So the constant is given by (93)23(−1)6=672
You have not incorporated the condition "... at least three of the squares are red" Guestonwebsite.
Go to https://www.desmos.com/calculator and simply type in your equation.
I guess this should look like: 2x−2x2−x−12
If so, it can be written as 2x−2(x−4)(x+3)
Express as partial fractions: 2x−2(x−4)(x+3)=Ax−4+Bx+3
from which we find
A+B=23A−4B=−2
i'll leave you to find A and B.
This is all I can think of (though the result is rather ugly!):
1. As follows:
Set y = 56, so 56 = -16*t^2 + 60*t
Divide by 16 and rearrange this: t^2 - (15/4)*t + (7/2) = 0
This factorises as (t - 7/4)*(t - 2) = 0
So, there are two times. Which do you think represents the answer to the question?