Alan

$(1+ax)^n=1+nax+\frac{n(n-1)}{2!}a^2x^2+\frac{n(n-1)(n-2)}{3!}a^3x^3+...$

Let  $na=10$

and    $\frac{n(n-1)}{2!}a^2=150$

and solve for a and n, then find c from $c=\frac{n(n-1)(n-2)}{3!}a^3$

Type the following in the calculator on the home page here and then press enter.

Here's number 1:

Try a similar approach for the others.

Answered here: https://web2.0calc.com/questions/probability_84132#r1 

This should help:

Like this:

Have a look at https://mathschallenge.net/library/number/sum_of_cubes 

As follows:

Like this:

Try https://www.mathsisfun.com/money/compound-interest.html