As follows:
Like so:
"i" is the, so-called, imaginary number, defined such that i^2 = -1; and z is known as a complex number.
(3+4i)^2 = 3^2 +2*3*4i + (4i)^2 = 9 + 24i + 16*i^2 = 9 + 24i + 16*(-1) = 9 + 24i - 16 = -7 + 24i
"Therefore, the polynomial f(x) = (1/6) x^3 satisfies both properties." Note that (1/6)x^3 is not a degree 5 polynomial.
84 ÷ 2
42 ÷ 2
21 ÷ 3
7 ÷ 7
1
One way as follows:
Like this:
\(1_3 = 1\\12_3=1*3+2=5\\212_3=2*9+1*3+2=23\\2121_3 =2*27+1*9+2*3+1=70\)
The angles in a triangle sum to 180° so you can find angle Q from this. Then use the sin rule: q/sin(Q) = p/sin(P) to find q.
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