In triangle PQR, M is the midpoint of PQ. Let X be the point on QR such that PX bisects angle QPR, and let the perpendicular bisector of PQ intersect AX at Y. If PQ = 36, PR = 22, QR = 26, and MY = 8, then find the area of triangle PQR
I was trying to draw the figure, and then
you threw me a curve when you said AX.
Where did that come from?
Then I saw that you have the values of all
three sides. You don't need anything else.
Add all three sides, then take half of it.
Call this "s".
36 + 22 + 26
s = —————— = 42
2
Then use the following to get the area. A = sqrt[(s)(s – a)(s – b)(s – c)]
This is called Heron's Formula.
A = sqrt[(42)(42 – 36)(42 – 22)(42 – 26)]
A = sqrt(42 • 6 • 20 • 16)
A = sqrt(80,640)
A = 283.97 square units
That answer looks weird,but it has
to be right ... it's Heron's Formula.
.