EinsteinJr

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$$\left | x \right |=\sqrt{x^2}$$ for any real number x

So: $$\left | -10 \right |-\left |4-13 \right |\\ =\left | -10 \right |-\left |-9\right |\\ =\sqrt{(-10)^2}-\sqrt{(-9)^2}\\ =\sqrt{100}-\sqrt{81}\\ =10-9\\ =1$$

$$\left(-{\mathtt{10}}\right){\mathtt{\,\times\,}}{\mathtt{6}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{45}} = {\frac{\left(-{\mathtt{60}}\right)}{{\mathtt{2}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{45}} = {\mathtt{\,-\,}}{\mathtt{30}}{\mathtt{\,\small\textbf+\,}}{\mathtt{45}} = {\mathtt{45}}{\mathtt{\,-\,}}{\mathtt{30}} = {\mathtt{15}}$$

Sorry, that was the smallest cookie I had under the hand I'll try to find a smaller one.

$${\mathtt{78}}{\mathtt{\,\times\,}}{\mathtt{85}}{\mathtt{\,\times\,}}{\mathtt{97}}{\mathtt{\,\times\,}}{\mathtt{62}}{\mathtt{\,\small\textbf+\,}}{\mathtt{63}}{\mathtt{\,\small\textbf+\,}}{\mathtt{91}}{\mathtt{\,\small\textbf+\,}}{\mathtt{83}} = {\mathtt{39\,873\,057}}$$

8/4 is 2 because 8=2*4

velocity=distance/time=>time=distance/velocity

$$t=\frac {d}v=\frac {1200}{7}=171.428571428571428571428571...$$

So it will take approximately 171.43 s.

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