(a)
\(-3(y+7)+39\le5(2-y)\\ -3y-21+39\le10-5y\\ -3y+18\le10-5y\\ 2y\le-8\\ \boxed{y\le-4}\)
(b)
\(2(7-v)+2v>15\\ 14-2v+2v>15\\ 14>15\\ \boxed{\text{no solution}}\)
never mind, it doesn't show.
The slope appears to be 8/3, and the y-intercept appears to be 1. So the equation is y=8/3x+1.
What is your question exactly? How to write fraactions? How to perform operations on them? Please specify :)
First we find the number of terms which is (103-1)/3+1=102/3+1=34+1=35. Now notice that every pair adds up to 103+1=104. So the sum is 104(35)/2=1820.
This question has been asked multiple times...you could look for it as well Guest.
We know Julius has 87 stamps. Liam has 10. Then let the number of stamps Mario have be x. We know Julius has three times as many stamps as Liam+Mario so we form an equation.
87=3(10+x)
87=30+3x
3x=57
x=19.
Therefore Mario has 19 stamps.
Try substituting all of this into the distance formula first and expand. See where you can go from there.
good job, looks like i was a little off...
Well from the diagram 3x-9 and 93 must add up to 180. So 3x-9=180-93 --> 3x-9=87. We solve for x to get 3x=96-->x=32.
+781 