MaxWong

This is so creative lol.

Q: Why have you posted this?

A: Because purple aliens do not wear orange hats as this is a culture.

When the central angle is expressed in radians:

S = r * theta

Where S is the arc length, r is the radius of the circle, and theta is the central angle in radians.

Therefore the arc length in this case is:

$\dfrac{37\pi}{11}$

Directly multiply.

First edit:

Whoops I did not see that take pi = 3.1416.

Therefore the answer should be $37/11 \times 3.1416\approx 10.57$

You probably have anaemia.

You're correct.

But how you do it in one step...... I took 2 steps at it:

$x^4 + x^2 + 1\\ =(x^2 + 1)^2 - x^2\\ =(x^2 -x+ 1 )(x^2+x+1)$

Step 2 I used a^2 - b^2 = (a+b)(a-b)

And pls do challenge the b part of the question I just posted.

6mx - 4m + 3rx - 2r

= 2m(3x - 2) + r(3x - 2)

= (2m + r)*(3x - 2)

PEDMAS or BODMAS.

PEDMAS is explained by Goken.

Brackets

Orders (Powers and n-th roots)

Division

Multiplication

Addition

Subtraction

Notice that addition is not addiction. Or you do some "addictions" in your math class.

If you are awesome, you answer 19.

If you are not-so-awesome, you answer 21.

If my assumptions are wrong, tell me.

That was question 2.

1)$6 - \log \dfrac{1}{2} x = 3\\ \log \dfrac{1}{2} x = 6 - 3 = 3\\ \dfrac{1}{2}x=10^3\\ x = 2\times 10^3 = 2000$

2)$\log(4x-3)+6 = 4\\ \log(4x-3)=-2\\ 4x-3 = 10^{-2}=\dfrac{1}{100}\\ 4x = \dfrac{301}{100}\\ x=\dfrac{301}{400}$

3)$\dfrac{2}{3}\log(5x) = 2\\ \log(5x) = 3\\ 5x = 10^3 = 1000\\ x = 200$

4)$2\log(250x)-6 = 4\\ 2\log(250x) = 10\\ \log(250x)=5\\ 250x = 10^5 = 100000\\ x = 400$

5)$5-2\log x = \dfrac{1}{2}\\ 2\log x = 5-\dfrac{1}{2}=\dfrac{9}{2}\\ \log x = \dfrac{9}{4}\\ x = 10^{9/4}=\sqrt[4]{10^9}=100\cdot\sqrt[4]{10}$