Melody

Thanks EP:

A note to the guest asker:

If you are having problems like this and you are registering an error, please indicate what part of the world that you live in.

or maybe

Gee you put so much effort into presenting that question well !

How could I possibly resist asnwering. 

2√5x+32=7

\(\qquad2\sqrt5 \;x+32=7\\ 2\sqrt5 \;x+32-32=7-32\\ \phantom{ wwwww }2\sqrt5 \;x=-25\\ \phantom{ wwwwwwww } x=\frac{-25}{2\sqrt5}\\ \phantom{ wwwwwwww } x=\frac{-25}{2\sqrt5}\times \frac{\sqrt5}{\sqrt5}\\ \phantom{ wwwwwwww } x=\frac{-25\sqrt5}{10}\\ \phantom{ wwwwwwww } x=\frac{-5\sqrt5}{2}\)

That is an interesting question.

I'll take a look

\(\frac{a}{b}=\frac{ak}{bk}=\frac{c}{d}\\ so\\ \frac{a+c}{b+d}=\frac{a+ak}{b+kb}=\frac{a(1+k)}{b(1+k)}=\frac{a}{b} \)

Are you happy with that?  Of course this only works if k is not equal to -1.  

okay    

LOL

How does the sun rotate 10 times in a day?  I suppose it could rotate on its own axis.

That would be really fast!

I cannot find a question in there???

Two sides of a parallelogram are 30 and 20.  One diagonal has a length of 40. What is the length of the other diagonal?

Use the cosine rule to find cos(theta)   then get back to me.      [ note:I want cos(theta), not  theta ]

If you have cos(theta), what is the value of cos(180-(theta)) ?\(\)

Thanks Hectictar,

I really like that \phantom one !  

And the \hspace{3cm}b  looks like it would be really useful.

It is good to have seome more commands that actually do work here  

I will add an a link to this thread, to the Latex thread that is found in the sticky notes.

While you are waiting to register, put your username at the bottom of your posts so that you can already start becoming known to other members.