Melody

921 Questions
34316 Answers

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Mathigon website

I just discovered a site called mathigon

https://mathigon.org/dashboard
lire plus ..

Melody 2 avr. 2022

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Reporting problems.

There are a number of people having problems at the moment.
If you lodge an error can you please give all relevant information that you can think of.
Where you are in the world - the city or the country - is often very important information. lire plus ..

Melody 16 mars 2022

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How to make an empty rectangle in Latex

I just worked out how to make an empty box of various horizonal size easily in LaTex.
This is not a recommended method, but other methods that I have tried here have not worked.
This coding is really simple. Just put letters inside lire plus ..

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Melody 15 mars 2022

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HAPPY ANNIVERSARY CHRIS! (CPhill)

I just realized that you became a member here exactly 8 years ago today!

It has been great to have you here all that time

Hors sujet

Melody 13 mars 2022

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WELCOME BACK CPHILL !

Melody 11 févr. 2022

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Very interesting question. No high level maths required.

This question was posted a couple of days ago.
https://web2.0calc.com/questions/geometry_73561

I think it is really interesting. It looks much more difficult than it really needs to be. lire plus ..

Melody 1 févr. 2022

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Members have a better experience. Their questions get more attention.

Almost everyone is posting as a guest.
If you post as a member your questions will have a far greater chance of a timely and helpful response.
If you are a genuine learner and interact with us, you will become known and answerers will do lire plus ..

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Melody 9 janv. 2022

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HAPPY BIRTHDAY CHRIS!

Melody 20 déc. 2021

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Some guidelines for question askers.

Please note:
1) Ask only one question per post.
2) When asking a question talk about what you have tried for yourself. Then people will take you more seriously and will be more able and willing to help.
3) If you get an answer lire plus ..

Hors sujet

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Melody 4 nov. 2021

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Remeniscing - a little historical humour.

I just found this old post that some of you, who have been around for a while, might find amusing.

https://web2.0calc.com/questions/look-at-the-new-leader-board

Hors sujet

Melody 29 oct. 2021

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0

simplify 7a/15b^2 + b/18ab

This is the question that you have asked, is it what you intended?

simplify [ (7a/15)*b^2] + (b/18) *ab

or did you really mean

simplify 7a/(15b^2) + b/(18ab)

or maybe you meant something else ??

Melody18 nov. 2013

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sorry, this isn't correct.
Try to google it to find the correct answer
Also, it is the surface area of a sphere that you want.

Melody18 nov. 2013

+118730

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Try working your way through a log unit
maybe
http://www.mathsisfun.com/algebra/logarithms.html

Melody18 nov. 2013

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How much mixture do you want to make up altogether?

Melody18 nov. 2013

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log(x) - (1/2)log(x+4) = 1

log(x) - log(x+4) ^1/2 = 1

log[x/(x+4) ^1/2] = 1

Now I need to know what base it is in. I will assume base 10
x/(x+4) ^1/2 = 10
etc
This will lead to a quadratic equation that you will have to solve.

You should work through a unit on logs maybe
http://www.mathsisfun.com/algebra/logarithms.html

Melody18 nov. 2013

+118730

0

((e^(100x)*(100sin(120pi*x)-120pi*cos(120pi*x))/(14400pi^2+10000))/e^(100x=Q What is Q?
I re-presented the question as follows - is this what the question was?

[ (e^(100x)*(100sin(120pi*x)-120pi*cos(120pi*x))/(14400pi^2+10000) ] /e^(100x)=Q What is Q?

Q = [ (e^(100x)*(100sin(120pi*x)-120pi*cos(120pi*x))/(14400pi^2+10000) ] /e^(100x)

Q = 100sin(x)- 120pi*cos(x)/(14400pi^2+10000)

Q = 1000[0.1sin(x)- [0.120pi/(14400pi^2+10000)]*cos(x)]
--------------------------------
Now using Sin(x-A)=sinx * cosA - sinA * cosx
let
cosA=0.1
sinA= 0.12pi/(14400pi^2+10000)
tanA=0.12pi/(14400pi^2+10000)/0.1 = 1.2pi/(14400pi^2+10000)
A = 2.47821*10^(-5) (to 6 sf)
-----------------------------------
Q = 1000*sin[ x - atan(1.2pi/(14400pi^2+10000))] exact if I didn't make a mistake
Q = 1000*sin[ x - 2.47821*10^(-5)] (this answer is not exact)

I think that's right but I could easily have made a mistake.

Melody18 nov. 2013

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11/50 * 870 Litres

It is actually
11Litres/50Km * 870km but the km cancel out. (You can cancel units just the same as you can cancel numbers)

Melody17 nov. 2013

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(1-sqrt(2))^2-1/(sqrt(2-1

Do you mean

(1-sqrt(2))^2- {1/(sqrt(2)} -1 ??

Melody17 nov. 2013

+118730

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Melody17 nov. 2013

+118730

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Draw the diagram
use pythagoras to ger the third side
Read the ratios off the diagram.

remmeber the word
soh cah toa
sin=o/h
cos=a/h
tan/o/a

or if you prefer, you can remember
Some old hags
Can't always hide
their old age

co t=1 / tan
co sec=1 / sin
se c=1 / cos

I am trying to show you that the
first letter of original ratio = third letter of new one.

Melody17 nov. 2013