MaxWong

y = 17 - x

when x = -6

y = 17 - (-6) = 17 +6 = 23

\(\frac{positive}{negative}=negative\)

To do this question, differentiate f(x) first.

\(f(x) = 6x^2+x\)

\(\frac{d}{dx}f(x) = f'(x) = 12x + 1\)

\(f'(a) = 12a +1\)

When a = 1,

\(f'(1) = 12(1) + 1 = 13\)

\(sin(-1) = -0.017452406\)

or do you mean \(sin^{-1}\)which is arcsin?

\(\frac{1}{2}\times4\times15\times8=2\times15\times8 = 30\times8 = 240\)

How could you overtake the second person before overtaking the third person?

111+113+115+117+119+131+133+135+137+......+199
+311+313+315+317+319+.....+399+

511+513+.....+599 +

711+713+715+717+.....+799+

911+.....+999

why i seperate it into 5 columns?

because the differences of the corresponding numbers in adjacent columns are all 200

there are 25 numbers in each column

so the sum equals (Let x be (111+113+......+199) because i am too lazy)

x+ (25*200+ x) + (25*200*2 + x) + (25*200*3 + x) + (25*200*4 + x)

if we can find out what the actual value of x is, the problem would be much easier

x = (110+ 111 + 112 + 113 + ...... + 199) - (110+112+114+116+......+198) - (120 + 122 + .... + 128) - (140 + 142 + 144 + ... +148) - (160 + 162 + ... +168) - (180 + 182 + ... + 188) 

= (110 + 199) * 90/2 - (110 + 198)* 45/2 - (120 + 128) *5/2 - (140 + 148) *5/2 - (160 + 168) *5/2 - (180+188)*5/2

= 13905 - 6390 - 620 - 720 - 820 - 920

= 4735

There we go!! We found the actual value of x

Next step we calculate x+ (25*200+ x) + (25*200*2 + x) + (25*200*3 + x) + (25*200*4 + x)

= 4735 + 5000 + 4735 + 10000 + 4735 + 15000 + 4735 + 20000 + 4735

= 73675

So the sum of all 3-digit numbers whose digits are all odd is 73675

P.S. I don't know and I don't understand any C or P. So I used my own method to do the problem

constant term = 0

because no 'constant term' exists

Rounding up 152.498395 : 152.50

Rounding down 152.498395 : 152.49

Rounding 152.498395 : 152.50