lolololol
Good joke :P
Law of Sine: \(\dfrac{a}{\sin A}=\dfrac{b}{\sin B}\)
You just find the sides and angles that you have and then substitute into the formula.
Then there must be one of the sides or angles unknown.
So simplify and solve for that unknown.
\(19\dfrac{4}{5}\div 2\\ =19\div 2 + \dfrac{4\div 2}{5}\\ =9\dfrac{1}{2}+\dfrac{2}{5}\\ =9.5 + .4\\ = 9.9\\ =9\dfrac{9}{10}\)
6(x-6)-5(x-7)=x+6
6x-36-5x+35 = x+6
x - 1 = x + 6 WHAT!????
Assume that y is a imaginary number, y = ai
e^(axi) - a^2 = sin(x + ai)
cos(ax) + i sin(ax) - a^2 = sin x cosh a + i cos a sinh b
This seems not solvable :(
Even if you don't round it is still 33.
\(99\times \dfrac{1}{3}\\ =99\div \dfrac{1}{\frac{1}{3}}\\ =99\div 3\\ =33\)
A way to remember what sin cos tan are for.
"SOHCAHTOA"
You just read it like So- Car- Toe- ah
Sine is Opposite over Hypotenuse
Cosine is Adjacent over Hypotenuse
Tangent is Opposite over Adjacent.
Find the asymptotes, local minimum, local maximum, by differentiation.
