Hmm.
Area of a regular hexagon = \(\dfrac{3\sqrt3 a^2}{2}\)
where a is the side length.
Therefore area of a regular hexagon whose perimeter is 24 ft. is \(3\sqrt3 \cdot 4^2\cdot \dfrac{1}{2}\\ =24\sqrt3\text{ sq. ft.}\)
For #2, I assume that the circle touches the side whose length is 14ft.
Then the area of shaded region is:
\(14\times 21 - \pi (7^2)\\ =(294-49\pi)\text{ sq. ft.}\)
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