Melody

8 ÷ (10−9) 3 × 7 + 4

There is a symbol missing between the bracket and the 3 maybe i3 is a power ?

8 ÷ (10−9)^3 × 7 + 4

\(8 ÷ (10−9) ^3 × 7 + 4\\ =8 ÷ (1) ^3 × 7 + 4\\ =8 ÷ 3× 7 + 4\\ =\frac{8 }{3}× 7 + 4\\ =\frac{8\times7 }{3}+ 4\\ =\frac{56}{3}+ 4\\ =18\frac{2}{3}+ 4\\ =22\frac{2}{3}\\\)

If it is parallel then it has to have the same gradient which is 4

So it has to be either 

H      y=4x+19

or

K      y=4x+21

Now it goes through (-5,1)

For H when x=-5     y= 4*-5 +19 = -20+19=-1 

For K when x=-5     y= 4*-5 +21 = -20+21= +1

So the answer is K 

Hi Mr O

I answered a question very simiar to this a day or two ago. I seem to recall you left a comment too..

Anyway, I'd like to see you attempt these questions, one at a time if you want, and then maybe we can talk about your answer/s.

Why don't you start with b, that looks like the easiest one because the only thing that matters is how many balls are in the boxes.

I think it is fair to assume that each candy must go into a lunch box.   :)

Yes you are right Helper 

It is much nicer dealing with people who have given themselves an identity. 

There are benefits to being a member to and people never get any email spam from this site so it is really nice for everyone when guests become members.   

Well you can fall asleep and dream about being sucessful and making money but your dream is more likely to come true if you stop complaining and do your homework  

You are welcome and if you send private messages that is really nice of you.    

It is also nice and important that you thank people publicly because it sets an example for others.

If new people do not see anyone else saying thank you then they are more likely to think that they, for some bizarre reason they are not supposed to say thanks.  People copy the behaviours of others. :)

Welcome to the forum by the way.  I know you have been here for over a month but that still isn't all that long.    

Evaluate:

Given: a=d/t2  and d=rt+1/2at2  

Find the values of a and t  when d=2 and r=3

\(Given: a=\frac{d}{t^2} \;\; and\;\;d=rt+\frac{1}{2}at^2\\\text{Find a and t when d=2 and r=3}\\~\\ a=\frac{2}{t^2}\;\;(1) \;\; and\;\;2=3t+\frac{1}{2}at^2\;\;(2)\\ at^2=2 \;\;\;(1b)\\ sub \;1b\;into\;2\\ 2=3t+\frac{1}{2}*2\\2=3t+1\\1=3t\\t=\frac{1}{3}\\ \text{sub back into (1)}\\ a=2\div\frac{1}{3^2}=2*9=18\\ so\;\;t=\frac{1}{3}\;\;and\;\;a=18 \)

Hello Manuel,

Why is it that you give your own questions points but you almost never give the answerers any points?

Also,

Why is it that you always say please, which is very nice, but you never say thank you?

We all use Desmos, it is a beautiful graphing calculator :)