This is a semi educated guess, I am not knowledgable about electricity.
Let E= k/d and C=md whee k and m are constants. (but we do not need to worry about C.)
and d is the distance between the chages.
Initially
\(\frac{k}{d}+\frac{k}{d}+\frac{k}{d}=\frac{3k}{d} = 15J \)
Now move the charge and the distances become d/2, d/2 and d
so new energy is
\(\frac{k}{d/2}+\frac{k}{d/2}+\frac{k}{d}=\frac{5k}{d} = 15*5/3\;Joules = 25J \)
So if my reasoning is correct there will be 10 more Joules of energy.