\(\color{blue}{\begin{array}{rll}(\dfrac{1}{27})^{x+2}+1&=&(\dfrac{1}{3})^{x-3}+1\\ (3^{-3})^{x+2}&=&(3^{-1})^{x-3}\\ 3^{-3x-6}&=&3^{3-x}\\ -3x - 6&=& 3-x\\ -2x&=&9\\ x&=&-\dfrac{9}{2}\end{array}}\)
#BlackLaTeXIsBoring.
Use your own calculator!! Each IP only have 3 chances to ask a question here using the identity 'Guest' so seize your asking chance unless you want to register to be a member!!
\(\color{olive}{\dfrac{\sqrt{71.15}}{107.9-70.4}\\ = 0.224934558}\\ \color{orange}\text{according to my calculator}\)
I assume you mean \(\pi\) by 3.14.
\(\begin{array}{rll}131 &=& \dfrac{1}{3}\cdot \pi \cdot r^2 \cdot 10\\ 393&=&10\pi r^2\\ r^2 &=& \dfrac{393}{10\pi}\\ r&=&\sqrt{\dfrac{393}{10\pi}}\end{array} \)
which is approx. 3.53688825481142
Thanks everyone :)
Probability of getting 3 odd numbers from the set {1,3,5,7,9,11,13,15} is 1
But Probability of adding 3 odd numbers and getting an even number is 0.
Therefore this problem is impossible.
hi :)
\((a+2)(a+2)\\ = a(a+2) + 2(a+2)\\ = (a)(a) + (2)(a) + (2)(a) + (2)(2)\\ = a^2 + 2a + 2a + 4\\ = a^2 +4a + 4\)
Btw the way you type is super cool. The Guest who asked the question.
In Maths, (I assume you mean 'e')
\(e=\displaystyle\sum^{\infty}_{0}\dfrac{1}{n!}\)
In Physics, E usually means energy like in the famous formula E = mc2
Btw the c in E = mc2 means the speed of light using the unit ms-1.
:)
\(\dfrac{13}{4}\times \dfrac{3}{2} \times \dfrac{1}{4} \times \dfrac{6}{5}\\ =\dfrac{13\times 3\times 6}{4\times 2\times 4\times 5}\\ =\dfrac{234}{160}\\ =\dfrac{117}{80}\)
This calculator is super cool that it can deal with big numbers, differentiations, integrations, modulus maths and more!!
