3x2+4x−2=0x?
An easy way!
"p,q-formula": x2+px+q=0
solution: x1,2=−p2±√p24−q
check: x1+x2=−px1x2=q
formula: 3x2+4x−2=0
prepare for "p,q-formula": 3x2+4x−2=0|:3
x2+43x−23=0p=43q=−23
solution: x1,2=−12(43)±√14(43)2+23
x1,2=−23±√43∗3+2∗33∗3
x1,2=−23±√103
x=x1=−2+√103=0.38742588672
x=x2=−2−√103=−1.72075922006
check: x1+x2=0.38742588672−1.72075922006=−1.ˉ3=−p
x1x2=0.38742588672×(−1.72075922006)=−0.ˉ6=q
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