From x + y + z = 8 and x - y + z = 4,
(x+y+z)−(x−y+z)=8−4=42y=4y=2
x+2+z=8x+z=6
√x+z−2+√2=√x+√z2+√2=√x+√zLet z=6−x2+√2=√x+√6−xSquare both sides,6+4√2=6+2√6x−x22√2=√6x−x2Square both sides again,8=6x−x2x2−6x+8=0(x−2)(x−4)=0x=2 or x=4When x=2,z=4When x=4,z=2The required ordered triples are (2,2,4) and (4,2,2)
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